5+0.1x+0.0003x^2=69

Solution for 5+0.1x+0.0003x^2=69 equation:

5+0.1x+0.0003x^2=69

We move all terms to the left:

5+0.1x+0.0003x^2-(69)=0

We add all the numbers together, and all the variables

0.0003x^2+0.1x-64=0

a = 0.0003; b = 0.1; c = -64;
Δ = b2-4ac
Δ = 0.12-4·0.0003·(-64)
Δ = 0.0868
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.1)-\sqrt{0.0868}}{2*0.0003}=\frac{-0.1-\sqrt{0.0868}}{0.0006}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.1)+\sqrt{0.0868}}{2*0.0003}=\frac{-0.1+\sqrt{0.0868}}{0.0006}
$